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28x^2-80x+48=0
a = 28; b = -80; c = +48;
Δ = b2-4ac
Δ = -802-4·28·48
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-32}{2*28}=\frac{48}{56} =6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+32}{2*28}=\frac{112}{56} =2 $
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